SOLUTION: what is the slope intercepy form of the linear equation with a graph that passes through (3,-5) and is perpendicular to the graph of the followin equation? 2x-3y=9

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Question 435268: what is the slope intercepy form of the linear equation with a graph that passes through (3,-5) and is perpendicular to the graph of the followin equation?
2x-3y=9

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.  

Line Perpendicular to 2x-3y=9  and passing thru Pt(3,-5)

 2x - 3y = 9  Or y = (-2/3)x -3  slope m = (-2/3)

New Line 

  y = (3/2)x + b

 -5 = (3/2)*-2 + b

 -2 = b

 y = (3/2)x - 2 (Blue Line)