SOLUTION: A line passes through (7, –6) and (8, –5). Write an equation for the line in point-slope form. Rewrite the equation in standard form using integers I need help with this one.

Algebra ->  Linear-equations -> SOLUTION: A line passes through (7, –6) and (8, –5). Write an equation for the line in point-slope form. Rewrite the equation in standard form using integers I need help with this one.      Log On


   

Question 433123: A line passes through (7, –6) and (8, –5). Write an equation for the line in point-slope form. Rewrite the equation in standard form using integers
I need help with this one. But I also need to know how to do for in the future.
Thank you
Found 2 solutions by stanbon, katealdridge:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A line passes through (7, –6) and (8, –5). Write an equation for the line in point-slope form. Rewrite the equation in standard form using integers
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slope = (-5--6)/(8/7) = 1/1 = 1
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Find the intercept:
y = mx + b:
-6 = 1*7 + b
b = -13
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Equation: y = x-13
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Standard form:
x-y = 13
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Cheers,
Stan H.

Answer by katealdridge(100) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for point-slope form is:
y-y%5B1%5D=m%28x-x%5B1%5D%29
The formula for finding the slope from 2 points is:
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
Find the slope first:
m=%28-5--6%29%2F%288-7%29
m=1%2F1=1
Then choose one of the points given to use in the pt-slope form, and plug in the slope also.
y--6=1%28x-7%29 This is the equation of the line in point slope form. To change it to standard form:
y%2B6=x-7 simplify a little first, then subtract x from both sides.
-x%2By%2B6=-7 then subtract 6 from both sides.
-x%2By=-13 this is the equation of the line in standard form.