SOLUTION: PRETTY PLEASE AGAIN consider the circle given by x^2 + (y+1)^2=9 a) Give the center aND RADIUS OF THE CIRCLE CENTER?___________ ___ rADIUS?___________ ____

Algebra ->  Linear-equations -> SOLUTION: PRETTY PLEASE AGAIN consider the circle given by x^2 + (y+1)^2=9 a) Give the center aND RADIUS OF THE CIRCLE CENTER?___________ ___ rADIUS?___________ ____       Log On


   



Question 42689: PRETTY PLEASE AGAIN
consider the circle given by x^2 + (y+1)^2=9
a)
Give the center aND RADIUS OF THE CIRCLE
CENTER?_______________
rADIUS?________________

Found 2 solutions by rapaljer, Nate:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
An equation in the form +%28x-h%29%5E2+%2B%28y-k%29%5E2+=+r%5E2 is the equation of a circle, whose radius is r, and whose center is at (h,k). In other words, you have to ZERO out the quantities that are squared, and those are the values that gives the center of the circle.

In your case, the center is at x=0 and y = -1, and the radius is r^2= 9, so r=3.

R^2 at SCC

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Standard form: (x - h)^2 + (y - k)^2 = r^2
(h,k) is your center while r is your radius
x^2 + (y + 1)^2 = 9
(x + 0)^2 + (y + 1)^2 = 9
center: (0,-1)
radius: 3