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Question 42060This question is from textbook algebra 1
: for the line passing through (-4,2)and (1,-2)
a. compute the slope
b. find another point with integer coordinates on this line.
Find the equation of each line below
a. the slope of the line is -3 and it passes though the poine of (-2.6)
-
2
b. the line passes through the the two points (1,-3)and (2,-1)
thank you. robbie
This question is from textbook algebra 1
Answer by ind_blade(2)   (Show Source):
You can put this solution on YOUR website! for the line passing through (-4,2)and (1,-2)
a. compute the slope
slope = (change in y) / (change in x)
= (-2 - 2) / (1 - (-4))
= ( -4 ) / 5 = -4/5
b. find another point with integer coordinates on this line.
equation of the line is : y= mx +b
y = -4/5 (x) + b at point (1,-2)
-2 = -4/5(1) + b so b = -6/5
general formula for the line is:
y = -4/5 (x) - 6/5 --> pick a value for x say 2 so:
y = -4/5 (2) - 6/5 = -8/5 - 6/5 = -14/5
so a point would be: (2, -14/5)
Find the equation of each line below
a. the slope of the line is -3 and it passes though the poine of (-2.6)
y = mx + b
y = -3x + b for point (-2, 6) b =
6 = -3(-2) + b
b = 0 so equation of line becomes --> y = -3x
b. the line passes through the the two points (1,-3)and (2,-1)
find slope like above: (-1 - (-3))/(2-1) = 2
y = 2x + b for point (2, -1) b =
-1 = 2(2) + b
b = -5
equation then is: y = 2x - 5
thank you. robbie
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