SOLUTION: how do you find the vertex of y=225-x^2

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Question 417554: how do you find the vertex of y=225-x^2
Found 2 solutions by ewatrrr, Gogonati:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex
y = -x^2 + 225 Vertex is (0,225) Parabola opens downward a = -1 < 0

Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
Answer;WE rewrite this equation ; (x-0)^2=-(y-225) This is the downward parabola with vertex the point (0,225).