SOLUTION: Having trouble understanding Slopes and graphs portion of my Algebra class. please help.
The problem is
Determine which two equations represent parallel lines.
(a) y = 6x – 1
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-> SOLUTION: Having trouble understanding Slopes and graphs portion of my Algebra class. please help.
The problem is
Determine which two equations represent parallel lines.
(a) y = 6x – 1
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Question 41453: Having trouble understanding Slopes and graphs portion of my Algebra class. please help.
The problem is
Determine which two equations represent parallel lines.
(a) y = 6x – 10 (b) y = –6x + 10 (c) y = 6x + 5 (d) y = x – 10
Thnks you Found 2 solutions by venugopalramana, AnlytcPhil:Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! Having trouble understanding Slopes and graphs portion of my Algebra class. please help.
The problem is
Determine which two equations represent parallel lines.
(a) y = 6x – 10 (b) y = –6x + 10 (c) y = 6x + 5 (d) y = x – 10
Thnks you
FOR LINES TO BE PARALLEL,THEY SHOULD HAVE SAME SLOPE
HERE
A.Y=6X-10...SLOPE=6
C.Y=6X+5....SLOPE=6
SO THEY ARE PARALLEL
B.HAS SLOPE OF -6 AND D.HAS SLOPE OF 1
Having trouble understanding Slopes and graphs portion of my Algebra class. please help.
The problem is
Determine which two equations represent parallel lines.
(a) y = 6x – 10 (b) y = –6x + 10 (c) y = 6x + 5 (d) y = x – 10
You need to know:
(1) that parallel lines have equal slopes.
and
(2) that y = mx + b is the equation of a linbe with slope = m [and
with y-intercept (0,b), although we don't need y-intercept here].
So compare each equation (a), (b), (c), and (d) with the
slope-intercept form y = mx + b
y = mx + b
-----------------
(a) y = 6x – 10 <--- Here the slope m is 6
(b) y = –6x + 10 <--- Here the slope m is -6
(c) y = 6x + 5 <--- Here the slope m is 6
(d) y = 1x – 10 <--- Here the slope m is 1
Thus (a) and (c) have the same slope and so are parallel.
The graph of (a) y = 6x – 10 is:
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The graph of (b) y = -6x + 10 is
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The graph of (c) y = 6x + 5 is
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The graph of (d) y = x – 10 is
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Edwin
