You can put this solution on YOUR website! I assume that your equation is [-5/ (2m)]-2(m-2).
1) First substitute in 1 for m.
[-5/ {2(1)} – 2[(1)-2]
2) Perform all operations in the parenthesis.
(-5/2) – 2(-1)
3) Distribute the -2, -2(-1) is a positive 2
(-5/2) +2
4) Change 2 into an improper fraction.
(-5/2) + 4/2
5) Your answer is -1/2
If however the equation is [-5/ m^2]-2(m-2), where m is raised to the second power then you would
1) First substitute in 1 for m.
(-5/ (1)^2) – 2[(1)-2]
2) Perform all operations in the parenthesis. 1 to the second power is 1x1, which equals 1
(-5/1) – 2(-1)
3) Distribute the -2
-5 +2
4) Add 2 to -5
Your answer is -3
There is a third option in which -5 is divided by everything to the right of the dividing line. If this is the case I would resubmit the question as, -5/ [2m – 2(m-2)] or -5/ [m^2 – 2(m-2)] depending on whether the 2 is a coefficient or a power.
You can put this solution on YOUR website! -5 ÷ m2 – 2(m – 2), for m = 1
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The problem is not clear.
Is m2 m squared? What is the denominator?
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