SOLUTION: In 1993 a farmer owned 250 acres. In 2004 he owned 312 acres. If this growth is linear, how many acres should he own in 2012. Write a linear equation to model his growth.

Algebra ->  Linear-equations -> SOLUTION: In 1993 a farmer owned 250 acres. In 2004 he owned 312 acres. If this growth is linear, how many acres should he own in 2012. Write a linear equation to model his growth.      Log On


   

Question 406720: In 1993 a farmer owned 250 acres. In 2004 he owned 312 acres. If this growth is linear, how many acres should he own in 2012. Write a linear equation to model his growth.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

In 1993 a farmer owned 250 acres.  In 2004 he owned 312 acres.

Using the point-slope formula, m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29

(2004,312)and

(1993,250) m = 62/11

Using the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept:  

 y = (62/11)x + 250   |x is the years beyond 1993

how many acres should he own in 2012  x = 19

 y = (62/11)*19 + 250 

 y = 107 + 250 = 357 acres