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Question 397345: I am trying to decide wether each pair of lines is Perpendicular, parallel, or neither. 2x-y=5, 2x+y=3
I have worked out:
2x-y=5
2x-y-5=5-5
2x-y-5=0
2x-y+y-5=0+y
2x-5=y
I plugged 2 in for x
2(2)-5=y
4-5=y
-1=y
2x+y=3
2x+3=y
Plugged in 2 for x again
2(2)+3=y
4+3=y
7=y
In my book it says that the answer is neither Perpendicular or parallel but I don't understand why that is. I thought if you were solving for y the coefficient of x is the slope so wouldn't the slope on both be 2?
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
2x-y = 5 OR y = 2x - 5 |good work!
2x+y=3 OR y = -2x + 3 |note subtracting 2x from both sides of the equation
Yes!! solving for y, the coefficient of x is the slope
to be parallel, line must have same slope
to be ⊥, lines must have slopes that are negative 'reciprocals' of one another
Neither is the case, therefore the lines are neither parallel or perpendicular.
However, Yes!, they do intersect at Pt (2,-1)...have that point in common
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