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Question 396327: whats the equation for the line perpendicular to y=6x+3 that contains (-6,2)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! what's the equation for the line
perpendicular to y=6x+3 that contains (-6,2)
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The given line has a slope of 6.
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Any line perpendicular to it must
have a slope of -1/6
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Form:
y = mx+b
Substitute and solve for "b":
2 = (-1/6)*-6 + b
2 = 1+b
b = 1
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Equation:
y = (-1/6)x + 1
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Cheers,
Stan H.
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