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Question 392500: (4y3+7y2-y-10)-(y2-5y+6) The 3 on the 4y is a exponent and same for the 7y for the 2 Please help me solve this problem.
Answer by haileytucki(390)   (Show Source):
You can put this solution on YOUR website! factored:
(4y^(3)+7y^(2)-y-10)-(y^(2)-5y+6)
Multiply -1 by each term inside the parentheses.
4y^(3)+7y^(2)-y-10-y^(2)+5y-6
Since 7y^(2) and -y^(2) are like terms, add -y^(2) to 7y^(2) to get 6y^(2).
4y^(3)+6y^(2)-y-10+5y-6
Since -y and 5y are like terms, subtract 5y from -y to get 4y.
4y^(3)+6y^(2)+4y-10-6
Subtract 6 from -10 to get -16.
4y^(3)+6y^(2)+4y-16
Factor out the GCF of 2 from each term in the polynomial.
2(2y^(3))+2(3y^(2))+2(2y)+2(-8)
Factor out the GCF of 2 from 4y^(3)+6y^(2)+4y-16.
2(2y^(3)+3y^(2)+2y-8)
simplied:
(4y^(3)+7y^(2)-y-10)-(y^(2)-5y+6)
Multiply -1 by each term inside the parentheses.
4y^(3)+7y^(2)-y-10-y^(2)+5y-6
Since 7y^(2) and -y^(2) are like terms, add -y^(2) to 7y^(2) to get 6y^(2).
4y^(3)+6y^(2)-y-10+5y-6
Since -y and 5y are like terms, subtract 5y from -y to get 4y.
4y^(3)+6y^(2)+4y-10-6
Subtract 6 from -10 to get -16.
4y^(3)+6y^(2)+4y-16
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