SOLUTION: solve he following system by substitution 8x-4y=16 y-2x-4

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Question 39089: solve he following system by substitution
8x-4y=16
y-2x-4
Answer by lyra(94) About Me  (Show Source):
You can put this solution on YOUR website!
8x-4y=16
y-2x-4
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++8%5Cx+%2B+-4%5Cy+=+16%2C%0D%0A++++-2%5Cx+%2B+1%5Cy+=+4+%29%0D%0A++We'll use substitution. After moving -4*y to the right, we get:
8%2Ax+=+16+-+-4%2Ay, or x+=+16%2F8+-+-4%2Ay%2F8. Substitute that
into another equation:
-2%2A%2816%2F8+-+-4%2Ay%2F8%29+%2B+1%5Cy+=+4 and simplify: So, we know that y=-8=0. Since x+=+16%2F8+-+-4%2Ay%2F8, x=-2.

Answer: system%28+x=-2%2C+y=-8=0+%29.


Hope this helps and feel free to contact me with further questions,
lyra