SOLUTION: I am having difficulty solving this problem, its a little more complicated than the last. Please help. 5(y+1)+2=8(y-1)+3

Algebra ->  Linear-equations -> SOLUTION: I am having difficulty solving this problem, its a little more complicated than the last. Please help. 5(y+1)+2=8(y-1)+3       Log On


   

Question 388521: I am having difficulty solving this problem, its a little more complicated than the last. Please help.
5(y+1)+2=8(y-1)+3
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5(y+1)+2=8(y-1)+3
5y+5+2 = 8y-8+3
-----
5y+7 = 8y-5
3y = 12
y = 4
---------------
Cheers,
Stan H.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

using the distributive Principle and combining Like terms 

  5(y+1)+2=8(y-1)+3 

 | Applying distibutive Principle

  5y +5 + 2 = 8y - 8 + 3

    5y + 7  = 8y - 5

 | combining like Terms by subtracting 5y from both sides of the equation

         7 = 3y - 5

 | combining like Terms by adding 5 to both sides of the equation

         12 = 3y

 | isolating y, the variable, on one side of the equation

 | Divided both sides by 3

          4 = y



CHECKING our Answer***

5(y+1)+2=8(y-1)+3 

 5*5 + 2 = 8*3 + 3 = 27