SOLUTION: What is the equation of a line that is perpendicular to the line y = 3x + 9 and containing the point (6, –4)?
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What is the equation of a line that is parallel to the line
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-> SOLUTION: What is the equation of a line that is perpendicular to the line y = 3x + 9 and containing the point (6, –4)?
and
What is the equation of a line that is parallel to the line
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Question 366438: What is the equation of a line that is perpendicular to the line y = 3x + 9 and containing the point (6, –4)?
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What is the equation of a line that is parallel to the line y=1/2x+7 equation and containing the point (–4, 7)? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! What is the equation of a line that is perpendicular to the line y = 3x + 9 and containing the point (6, –4)?
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y=3x+9
slope = 3
slope of line perpendicular to this line will be negative reciprocal
= -1/3
Point(6,-4)
equation of line passing through point (x1,y1)
=(y-y1)=m(x-x1)
=(y-(-4)=-1/3(x-6)
=y+4 = -x/3+2
y=-1/3*x -4+2
y= -1/3 *x -2
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The graph will be as below
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What is the equation of a line that is parallel to the line y=1/2x+7 equation and containing the point (–4, 7)?
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y= 1/2 x +7
slope = 1/2
since line required is parallel slope will be same = 1/2
Point ( -4,7)
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y-y1=m(x-x1)
y-7=1/2(x+4)
y-7= x/2 +2
y=x/2 +9
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