SOLUTION: Find the equation of the line that passes through the point(8,-5) and is perpendicular to the line 4x-12y=6. According to the teacher the answer is: y=-3x+19, but I don't underst

Algebra ->  Linear-equations -> SOLUTION: Find the equation of the line that passes through the point(8,-5) and is perpendicular to the line 4x-12y=6. According to the teacher the answer is: y=-3x+19, but I don't underst      Log On


   

Question 364877: Find the equation of the line that passes through the point(8,-5) and is perpendicular to the line 4x-12y=6. According to the teacher the answer is:
y=-3x+19, but I don't understand how.
Thankyou
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First find the slope of the line.
Convert to slope-intercept form, y=mx%2Bb%7D%7D%2C+where+%7B%7B%7Bm is the slope.
4x-12y=6
12y=4x-6
y=%281%2F3%29x-1%2F2
m%5B1%5D=1%2F3
Perpendicular lines have slopes that are negative reciprocals.
m%5B1%5D%2Am%5B2%5D=-1
%281%2F3%29%2Am%5B2%5D=-1
m%5B2%5D=-3
So the new line has the form,
y=-3x%2Bb
Use the point (8,-5) to solve for b,
-5=-3%288%29%2Bb
-5=-24%2Bb
b=24-5
b=19
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highlight%28y=-3x%2B19%29
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