SOLUTION: Consider the curve y= 2/x with x>0. The normal to the curve y= 2x at point P untersects the y axis at (0,-3). Find the point P?
I understand the gradient of the normal is -2/x^2 a
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-> SOLUTION: Consider the curve y= 2/x with x>0. The normal to the curve y= 2x at point P untersects the y axis at (0,-3). Find the point P?
I understand the gradient of the normal is -2/x^2 a
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Question 364612: Consider the curve y= 2/x with x>0. The normal to the curve y= 2x at point P untersects the y axis at (0,-3). Find the point P?
I understand the gradient of the normal is -2/x^2 and the equation using (0,-3)
making 2/x = -2/x^2-3 so -2/x^2-2/x-3 but can't think of where else to go
Note: At somepoint in the in solving this problem you may be required to solve a non trivial possibly high degree polynomial equation. in that case trial and error may be required but note that the answer should be a possitive integer smaller than 5 Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! I'm confused by your question.
Consider . OK
The normal to the curve ?
Should this be normal to the curve ?
