Question 363842: find a point on the x axis that is equidistant from (-1,-1) and (7,7)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find a point on the x axis that is equidistant from (-1,-1) and (7,7)
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Let the point be (x,0); solve for "x":
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Equation:
distance = distance
(x+1)^2 + (-1)^2 = (x-7)^2 + 7^2
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x^2 + 2x + 2 = x^2 - 14x + 98
16x = 96
x = 6
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Point: (6,0)
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Cheers,
Stan H.
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