SOLUTION: find an equation for the line that satisfies the given condition. (3,-2) purpendicular to the line x+4y+8=0 *show work

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Question 359089: find an equation for the line that satisfies the given condition.
(3,-2) purpendicular to the line x+4y+8=0
*show work
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%2B4y%2B8=0+
Convert to slope-intercept form, y=mx%2Bb
4y=-x-8
y=-%281%2F4%29x-2
Slope:m=-1%2F4
Perpendicular lines have slopes that are negative reciprocals,
m%5B1%5D%2Am%5B2%5D=-1
-%281%2F4%29%2Am%5B2%5D=-1
m%5B2%5D=4
Use the slope-intercept form,
y=4x%2Bb
Use the point to solve for b.
-2=4%283%29%2Bb
b=-2-12
b=-14
Complete the calculation to get b, then put it all together, to get the equation of the perpendicular line.
y=4x-14
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