SOLUTION: write an equation for the line perpendicular to y = 3x - 5 that contains (4,-2).

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Question 356860: write an equation for the line perpendicular to y = 3x - 5 that contains (4,-2).
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
m%5B1%5D%2Am%5B2%5D=-1
3%2Am%5B2%5D=-1
m%5B2%5D=-1%2F3
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Use the point-slope form of a line,
y=-%281%2F3%29x%2Bb
Use the point to solve for b,
-2=-%281%2F3%294%2Bb
b=-6%2F3%2B4%2F3
b=-2%2F3
highlight%28y=-%281%2F3%29x-2%2F3%29
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

Note: perpendicular lines have slopes that are negative reciproclas of one another

line perpendicular to  y = 3x - 5 would have a slope -1/3

Using slope intercept form of an equation for that line

y = (-1/3)x + b

Using Pt(4,-2) to find b

-2 = (-1/3)*4 + b

-2/3 = b

Line is y = (-1/3)x - (2/3)