SOLUTION: write an equation of the line that passes through ( 6,-10) and is perpendicular to the line that passes through ( 4,-6) and (3,-4)

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Question 355462: write an equation of the line that passes through ( 6,-10) and is perpendicular to the line that passes through ( 4,-6) and (3,-4)
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The slope of the line pasing through (4,-6) and (3, -4) is
%28-4-%28-6%29%29%2F%283-4%29+=+2%2F%28-1%29=+-2. The slope of the line perpendicular to this is equal to its negative reciprocal: 1/2. Therefore the equation of the line with slope 1/2 and passing through (6,-10) is
y-%28-10%29+=+%281%2F2%29%28x-6%29, or
y+%2B+10+=+%281%2F2%29%28x-6%29,
y+=+%281%2F2%29x-3-10,
y+=+%281%2F2%29x-13.