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Question 34632This question is from textbook College algebra
: Question; Write and equation (a) in standard form and (b) in slope-intercept form. # 38. Through(-2,0), perpendicular to 8x-3y=7
I really don't understand what "Through" means? I don't understand the equation either. But I really don't get through. Thanks so very much!
This question is from textbook College algebra
Answer by kietra(57)   (Show Source):
You can put this solution on YOUR website! There is a lot to this question, so lets first start with parts a and b. I am not sure if you have to have a specific or general equation. Standard form of an equation is ax + by = c. You can have any numbers for a,b,and c. Slope intercept form is y=mx+b and m and b could be any numbers. For #38- it wants you to find an equation that goes through the point (-2,0) and is perpendicular to 8x-3y=7. I hope that makes sense- maybe it will make more as we keep going. Lets start with 8x-3y=7. In order for two lines to be perpendicular, the product of their slopes has to be -1, or they have to be inverses. Lets first find the slope of 8x-3y=7. Put that equation in slope intercept form:
8x - 3y = 7
-3y = -8x + 7
y = 8/3x - 7/3
The only important number in this equation is 8/3 - that is the slope of this equation. So, the slope of a line perpendicular to that would be its inverse or -3/8.
Now, we have the slope of the line and a point that this line goes through (-2,0). Lets use point slope form (because we know a point and the slope) to find the equation of the line. POint slope is  where (x1,y1) is the point on our line.
Lets substitute: 
Now solve for y to get it into slope intercept:
Now, to get in standard form, put x back on the same side with y and get rid of your fraction:
Multiply everything by 8 to get rid of fractions
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