SOLUTION: Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form. Thank you Alisha

Algebra ->  Linear-equations -> SOLUTION: Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form. Thank you Alisha      Log On


   



Question 339835: Write the equation of the line which passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form.
Thank you
Alisha

Found 2 solutions by mananth, Fombitz:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
passes through (2, –3) and is perpendicular to y = 4x + 7 in standard form.
y= 4x +7
compare with y = mx +b
so slope = m = 4.
passes through (2,-3)
find b
plug value of x & y in the general equation
-3 = 2*4 +b
-3 = 8 +b
b= -11
the required line is perpendicular to the line y = 4x +7
so its slope will be -1/4
..
The equation will be y = (-1/4)x -11

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
m1%2Am2=-1
4%2Am2=-1
m2=-1%2F4
Now use the slope-intercept form, y=mx%2Bb
y=-%281%2F4%29x%2Bb
Use the point (2,-3) to solve for b.
-3=-%281%2F4%29%282%29%2Bb
-3=-1%2F2%2Bb
b=-5%2F2
.
.
.
highlight%28y=-%281%2F4%29x-5%2F2%29
.
.
.