SOLUTION: Write the equation of the line that is perpendicular to the line 3x - 2y = 6 and passes through the point (-1,2).

Algebra ->  Linear-equations -> SOLUTION: Write the equation of the line that is perpendicular to the line 3x - 2y = 6 and passes through the point (-1,2).       Log On


   

Question 332855: Write the equation of the line that is perpendicular to the line 3x - 2y = 6 and passes through the point (-1,2).

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
3x - 2y = 6 and passes through the point (-1,2).
-2y=-3x+6
y=-3x/-2+6/-2
y=3x/2-3 (red line)
This line has a slope=3/2
Thus a perpendicular line will have a slope=-2/3.
2=-2/3*-1+b
2=2/3+b
b=2-2/3
b=(2*3-2)/3
b=(6-2)/3
b=4/3 is the Y intercept.
Y=-2X/3+4/3. (green line)
+graph%28+200%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+3x%2F2+-3+%2C+-2x%2F3+%2B4%2F3%29+ (graph 200x200 ixels, x from -5 to 5, y from -5 to 5, of TWO functions 3x/2 -3 and -2x/3 +4/3).