SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper. f(x)=x^2-4x-4

Algebra ->  Linear-equations -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper. f(x)=x^2-4x-4      Log On


   

Question 328737: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper. f(x)=x^2-4x-4
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square to put into vertex form,y=a%28x-h%29%5E2%2Bk where (h,k) is the vertex.
f%28x%29=%28x%5E2-4x%29-4
f%28x%29=%28x%5E2-4x%2B4%29-4-4
f%28x%29=%28x-2%29%5E2-8
Comparing, the vertex is (2,-8).
THe vertex lies on the line of symmetry, x=2.
The parabola opens upwards since the coefficient of the x%5E2 term is positive so the function value at the vertex is a minimum.
ymin=-8
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Verify by graphing,
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