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Question 323010: 3r-5s=21
5r+3s=33
solve by elimination method
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 3r-5s=21
5r+3s=33
solve by elimination method
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Multiply 1st by 5
Multiply 2nd by 3
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15r - 25s = 105
15r + 9s = 99
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Subtract 1st from 2nd to get:
34s = -6
s = -3/17
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Substitute into 3r-5s = 21 to solve for r:
3r -5(-3/17) = 21
3r = 21 -15/17
r = 7 - 5/17
r = 114/17
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Cheers,
Stan H.
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