SOLUTION: what is the standard form for the equation of the line which passes through the point (5, 2) and which has a y-intercept of 7. what is the standard form for the equation of the

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Question 321319: what is the standard form for the equation of the line which passes through the point (5, 2) and which has a y-intercept of 7.
what is the standard form for the equation of the line which passes through the point (–1, –2) and is parallel to the line that has an equation of 6x + 2y = 4.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first problem to get you started.

If you want to find the equation of line with a given a slope of 7 which goes through the point (5,2), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y-2=7%28x-5%29 Plug in m=7, x%5B1%5D=5, and y%5B1%5D=2 (these values are given)


y-2=7x%2B%287%29%28-5%29 Distribute 7


y-2=7x-35 Multiply 7 and -5 to get -35


y=7x-35%2B2 Add 2 to both sides to isolate y


y=7x-33 Combine like terms -35 and 2 to get -33


-7x%2By=-33 Now subtract 7x from both sides.


7x-y=33 Multiply EVERY term by -1 to make the x coefficient positive.

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Answer:


So the equation of the line, in standard form, with a slope of 7 which goes through the point (5,2) is 7x-y=33