SOLUTION: The problem question is :Write an equation of the line passing through (-4, 4) with slope 5. Give the answer in slope-intercept form. Use y as the dependent variable and x as the i

Algebra ->  Linear-equations -> SOLUTION: The problem question is :Write an equation of the line passing through (-4, 4) with slope 5. Give the answer in slope-intercept form. Use y as the dependent variable and x as the i      Log On


   

Question 319159: The problem question is :Write an equation of the line passing through (-4, 4) with slope 5. Give the answer in slope-intercept form. Use y as the dependent variable and x as the idependent variable.
Please help, I'm having a hard time with this one.
Found 2 solutions by Fombitz, jim_thompson5910:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the point-slope form of a line,
y-yp=m%28x-xp%29 where m is the slope and (xp,yp) is the point.
.
.
.
y-4=5%28x-%28-4%29%29
y-4=5%28x%2B4%29
y-4=5x%2B20
highlight_green%28y=5x%2B24%29

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since we have "an equation of the line passing through (-4, 4) with slope 5", we know that m=5, x=-4 and y=4


y=mx%2Bb Start with the general slope intercept equation.


4=%285%29%28-4%29%2Bb Plug in m=5, x=-4 and y=4


4=-20%2Bb Multiply 5 and -4 to get -20


4%2B20=b Add 20 to both sides.


24=b Add.


So the value of 'b' is b=24.


So m=5 and b=24. Plug these values into y=mx%2Bb to get y=5x%2B24


So the equation of the line with slope 5 which goes through (-4,4) is y=5x%2B24