SOLUTION: Please help me!! -10y+8(3-y)+20 = 3+2*4*y-y

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Question 318657: Please help me!! -10y+8(3-y)+20 = 3+2*4*y-y
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
-10y%2B8%283-y%29%2B20+=+3%2B2%2A4%2Ay-y Start with the given equation.


-10y%2B8%283-y%29%2B20+=+3%2B8y-y Multiply.


-10y%2B24-8y%2B20=3%2B8y-y Distribute.


-18y%2B44=3%2B8y-y Combine like terms on the left side.


-18y%2B44=7y%2B3 Combine like terms on the right side.


-18y=7y%2B3-44 Subtract 44 from both sides.


-18y-7y=3-44 Subtract 7y from both sides.


-25y=3-44 Combine like terms on the left side.


-25y=-41 Combine like terms on the right side.


y=%28-41%29%2F%28-25%29 Divide both sides by -25 to isolate y.


y=41%2F25 Reduce.


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Answer:

So the solution is y=41%2F25