SOLUTION: The line is perpendicular to x-5y=4 and passes through the point (-1,1)

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Question 315640: The line is perpendicular to x-5y=4 and passes through the point (-1,1)
Answer by moshiz08(60) About Me  (Show Source):
You can put this solution on YOUR website!
First we must find the slope of the line x-5y=4. We shall put it into slope-intercept form.
x-5y=4
x+=+4+%2B+5y+
5y+=+x+-+4+
y+=+%28x%2F5%29+-+%284%2F5%29+
The slope of this line is m=1%2F5. The slope of a line perpendicular to this is -5.
The line must pass through the point (-1,1).
We can give the equation of the line now in point-slope form: y+-+y_0+=+m%28x-x_0%29+, where m=-5, x_0+=+-1, and y_0+=+1.
So our equation is y+-+1+=+-5+%28x+-+%28-1%29+%29+.
We can convert this to slope-intercept form too:
y+-+1+=+-5+%28x+%2B+1%29+
y+-+1+=+-5x+-+5+
So the line in slope-intercept form is: +y+=+-5x+-+4+
Also, we can convert this to standard form as: +5x+%2B+y+=+-4+.
I hope this helps!