SOLUTION: Write the slope-intercept form of an equation of the line that passes through the given point (4,-1) and is perpendicular to the graph of 7x-2y+3 (show work)
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-> SOLUTION: Write the slope-intercept form of an equation of the line that passes through the given point (4,-1) and is perpendicular to the graph of 7x-2y+3 (show work)
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Question 301408: Write the slope-intercept form of an equation of the line that passes through the given point (4,-1) and is perpendicular to the graph of 7x-2y+3 (show work) Answer by solver91311(24713) (Show Source):
Step 1: Find the slope of the line represented by the given equation. Since the given equation is in standard form, use the negative of the coefficient on divided by the coefficient on . Alternatively, you can solve the equation for to put the given equation into slope intercept form. Having done that, the slope of the line represented by the given equation is equal to the coefficient on .
Step 2: Determine the slope of the desired line. Calculate the negative reciprocal of the slope of the given line because:
Step 3: Derive an equation of the desired line using the point-slope form of the equation of a line:
where is the given point and is the slope calculated in Step 2.
Step 4: Solve the equation derived in Step 3 for . That is to say rearrange the equation so that is all by itself on the left side of the equals sign and everything else is on the right side. The equation will then be in the form which is the slope intercept form.
I can't actually solve your problem for you because you didn't actually give us an equation of a line to work with. You wrote which is not an equation. I can't tell whether you really meant or . Besides, I don't want to deprive you of the fun and excitement of getting the answer by yourself.
