SOLUTION: write the equation of the line (in slope intercept form) that passes through the point (7,5) and is perpendicular to the line x-2y=7. First I got y on the left side: y=x/2-7/2 No

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Question 295813: write the equation of the line (in slope intercept form) that passes through the point (7,5) and is perpendicular to the line x-2y=7.
First I got y on the left side: y=x/2-7/2
Now I really don't know what to do. Please help.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
write the equation of the line (in slope intercept form) that passes through the point (7,5) and is perpendicular to the line x-2y=7.
First I got y on the left side: y=x/2-7/2
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Since y = (1/2)x -(7/2)
the slope of any line that is perpendicular to it
is -2.
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Then you can find the equation you are looking for.
Form is y = mx + b
m = -2 and y = 5 when x = 7.
Substitute and solve for "b":
5 = -2(7) + b
5 = -14 + b
b = 19
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Equation is: y = -2x+19
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Cheers,
Stan H.
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