SOLUTION: Given that the graph of the equation y = 2x+7/square root of 9-4x²,intersects the x axis once, how do I calculate the coordinates of this point of intersection

Algebra ->  Linear-equations -> SOLUTION: Given that the graph of the equation y = 2x+7/square root of 9-4x²,intersects the x axis once, how do I calculate the coordinates of this point of intersection       Log On


   

Question 288598: Given that the graph of the equation y = 2x+7/square root of 9-4x²,intersects the x axis once, how do I calculate the coordinates of this point of intersection
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Intersecting the x axis means y is zero
set your equation to y=0 and solve for x.
Is this the problem?

y=%282x%2B7%29%2F%28sqrt%289-4x%5E2%29%29
x=-7/2
0+=+%282+x%29%2Fsqrt%289-4+x%5E2%29%2B7%2Fsqrt%289-4+x%5E2%29
2x+7=0
2x=-7
x=-7/2