SOLUTION: The area of a rectangular tabletop is 6 square feet. If the width is 2 feet shorter than the length, then what are the dimensions?
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-> SOLUTION: The area of a rectangular tabletop is 6 square feet. If the width is 2 feet shorter than the length, then what are the dimensions?
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Question 286170: The area of a rectangular tabletop is 6 square feet. If the width is 2 feet shorter than the length, then what are the dimensions? Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! L = length
W = width
A = area = L*W = 6 sq. ft
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L = W+2
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Substituting...
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(W+2)*W = 6
W^2 + 2W = 6
W^2 + 2W -6 =0
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We cannot factor it, so use the quadratic equation...
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Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=28 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: 1.64575131106459, -3.64575131106459.
Here's your graph:
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A negative width is nonsensical, so we'll go with W = approximately 1.6457.
Substituting W=1.6457, we can find L.
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L = W+2 = 1.6457 + 2 = 3.6457
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Checking this solution, is the Area = 6?
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1.6457*3.6457 =5.9997, which within the rounding error caused by using the approximation W = 1.6457.
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Done.