|
Question 286151: Find an equation of the the line satisfying the given conditions.
Through (-2, 4); parallel to 9x - 6y = -54
Found 2 solutions by checkley77, Alan3354:
Answer by checkley77(12844)   (Show Source):
You can put this solution on YOUR website! Through (-2, 4); parallel to 9x - 6y = -54
-6Y=-9X-54
Y=-9X/-6-54/-6
Y=3X/2+9 (RED LINE)
THIS LINE HAS A SLOPE=3/2 THUS A PARALLEL LINE WILL ALSO HAVE A SLOPE OF 3/2.
4=3/2*-2+b
4=-6/2+b
4=-3+b
b=4+3
b=7
Y=3X/2+7 (GREEN LINE)
 (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions 3x/2 +9 and 3x/2 +7).
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 13
The slope, m = -3
------------------
The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
------------------------
For further assistance, or to check your work, email me via the thank you note.
|
|
|
| |
