SOLUTION: use the slope and y-intercept to graph the equation {{{y=2/3}}}{{{x+1}}}

The y-intercept is the point (0,1), since  is the last number in the equation
.  Find 1 on the y-axis.  Put a dot there:



Now look at the slope, which is , because it is the coefficient
in the equation  It has a numerator and a 
denominator (if it were just a whole number you would put a 1 under
it so it would have a numerator and a denominator)

The slope is positive, so we start at the point 1 on the y-axis, and
from there we draw a line UPWARD the number of units of the NUMERATOR 2.
That is, we draw this green line UPWARD which is 2 units long:



(You don't have to put an arrowhead on it like I did to
show that we went UPWARD.) 
[If the slope had been negative, we would have drawn
it DOWNWARD)]

Now from that arrowhead, turn RIGHT (always RIGHT, even when the
slope is negative) and draw a line to the RIGHT which is the same 
number of units long as the DENOMINATOR of the slope, which is 3.
So we draw this horizontal line from that arrowhead. I'll put
another arrowhead on it, but of course you don't have to, but you
can if you like :-)




Next get a ruler and draw a line through the point you
started at, the y-intercept (1,0) through that second
arrowhead like this:



That's the graph of the equation 

Edwin