SOLUTION: 2x/3 + 3y/4 = 11/12 x/3 + 7y/18 = 1/2

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Question 278284: 2x/3 + 3y/4 = 11/12
x/3 + 7y/18 = 1/2
Found 2 solutions by mananth, stanbon:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
2x/3 + 3y/4 = 11/12
x/3 + 7y/18 = 1/2

8x+9y= 12*11/12
8x+9y=11----------------1

x/3 +7y/18 =1/2
6x+7y= 1/2*18
6x+7y=9-----------------2
Multipy equation 1 by 3 and equation 2 by 4

24x+27y=33
24x+28y=36
-y=-3
y=3
Subsyitute the value of y in equation 1 an you get x=-2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2x/3 + 3y/4 = 11/12
x/3 + 7y/18 = 1/2
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Multiply thru 1st equation by 12
Multiply thru 2nd equation by 18
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8x + 9y = 11
6x + 7y = 9
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Multiply thru 1st equation by 6
Multiply thru 2nd equation by 8
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48x + 54y = 66
48x + 56y = 72
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Subtract 1st from 2nd1st and solve for "y":
2y = 6
y = 3
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Substitute into 6x+7y = 9 to solve for "x":
6x + 7*3 = 9
6x = -12
x = -2
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Cheers,
Stan H.