SOLUTION: Given the graph below, how do I determin the rise, run, & slope? Also, how do I determine the equation so I can write it in standard form? {{{graph (600,600,-10,10,-10,10,(1/4

Algebra ->  Linear-equations -> SOLUTION: Given the graph below, how do I determin the rise, run, & slope? Also, how do I determine the equation so I can write it in standard form? {{{graph (600,600,-10,10,-10,10,(1/4      Log On


   

Question 274059: Given the graph below, how do I determin the rise, run, & slope? Also, how do I determine the equation so I can write it in standard form?
graph+%28600%2C600%2C-10%2C10%2C-10%2C10%2C%281%2F4%29%2Ax+%2B+2%29

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I decide to put the equation in the form
y+=+mx+%2B+b where m is the slope
and b is the y-intercept
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First, I look at where the line crosses
the y-axis. It's at the point (0,2)
Plugging this into the general formula,
2+=+m%2A0+%2B+b
b+=+2
This is the y-intercept
-----------------------
The easiest way to read off the slope is
from x-intercept to y-intercept or
from y-intercept to x-intercept
---------------------------------
Slope is change in y over change in x
Say I start at the x-intercept which is
at (-8,0) and I end at (0,2), the y-intercept
slope is %28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29
which is %282+-+0%29%2F%280+-+%28-8%29%29+=+1%2F4
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Say I go in the other direction:
(0,2) to (-8,0)
The slope is %280+-+2%29%2F%28-8+-+0%29+=+1%2F4
I get the same answer as I should.
So, setting m+=+1%2F4, the equation is
y+=+%281%2F4%29%2Ax+%2B+2 Then put it in standard form