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Question 273309: Find an equation of the line containing the given pair of points.
(1,4) and (3,5)
I found m first 5-4/3-1 = 1/2
Then through other sources told me to use this formula
y-y^1=m(x-x^1)
y-4=1/2(x-1)
y-4=1/2x(1/2)(-1/1)
y=1/2x-1/2+4
y=1/2x-2
But the answer is y=1/2x+7/2
Where did I go wrong? Please could you show me how do this by step by step?
Thank you
JPA
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find an equation of the line containing the given pair of points.
(1,4) and (3,5)
I found m first 5-4/3-1 = 1/2
Then through other sources told me to use this formula
y-y^1=m(x-x^1)
y-4=1/2(x-1)
---------------
y-4 = x/2 - 1/2
y = x/2 + 7/2
----------------
y-4=1/2x(1/2)(-1/1) ???
y=1/2x-1/2+4 This is y = (1/2)x - (1/2) + 4 = (1/2)x + 7/2
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A better method, after finding the slope, is to use:
y = mx + b and find b. (Use either point)
4 = (1/2)*1 + b
b = 7/2
--> y = (1/2)x + 7/2
--------------------
The lack of parentheses is confusing, even to you.
y=1/2x-2
But the answer is y=1/2x+7/2
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