SOLUTION: identify the slope and y intercept of the graph of the equation. then graph.
y= -5/4x+1
I am not sure how to graph this and is the answer -4/5;y-intercept:-1 or am I wrong
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-> SOLUTION: identify the slope and y intercept of the graph of the equation. then graph.
y= -5/4x+1
I am not sure how to graph this and is the answer -4/5;y-intercept:-1 or am I wrong
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Question 269406: identify the slope and y intercept of the graph of the equation. then graph.
y= -5/4x+1
I am not sure how to graph this and is the answer -4/5;y-intercept:-1 or am I wrong Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! Your problem statement is in y=mx+b (slope intercept) form
m = slope = -4/5
.
The y intercept is the value of the y coordinate when x=0
So it is 1.
.
.
We know a negative slope means the line runs from the upper left to the lower right.
We can see that is the case by looking at the graph.
.
We also can consider the x intercept as a check.
The x intercept is the x coordinate when y=0.
0 = -4/5x + 1
Adding 4/5x to both sides
4/5x = 1
Multiply both sides by 5
4x = 5
Dividing both sides by 4
x = 5/4 = 1.25
So, we expect to cross the x intercept at 1.25, which we can see on the graph.
Of course, you can substitute other values that ought to be on the line and check to see if they're on the graph.
For example, if x=5, then y = -4/5*5 + 1 = -3.
That checks.
Done.