SOLUTION: Intermediate Algeba Use Issue: Find three consecutive integers such that the sum of the first and twice the second is 122 minus three times the third.

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Question 266767: Intermediate Algeba
Use Issue: Find three consecutive integers such that the sum of the first and twice the second is 122 minus three times the third.

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+1, and x+2 be the integers
From above ,we get
x+%2B+2%2A%28x%2B1%29+=+122+-+3%2A%28x%2B2%29
distribute to get
x+%2B+2x+%2B+2+=+122+-3x+-+6
combine like terms to get
3x+%2B+2+=+116+-+3x
add 3x and subtract 2 to get
6x+=+114
divide to get
x+=+19
the three numbers are 19, 20, and 21