SOLUTION: From Intermediate Algebra: Find the three consecutive integers such that the sum of the first and twice the second is 122 minus three times the third.

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Question 266542: From Intermediate Algebra:
Find the three consecutive integers such that the sum of the first and twice the second is 122 minus three times the third.
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+1, and x+2 be the numbers.
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From above, we get
(i) x%2B+2%2A%28x%2B1%29+=+122+-+3%2A%28x%2B2%29
simplify to get
(ii) 3x%2B+2+=+-3x+%2B+116
add 3x to get
(iii) 6x%2B+2+=+116
subtract 2 to get
(iv) 6x+=+114
divide to get
x = 19
so, we get
19, 20, and 21.