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Question 266324: Solve each problem involving consecutive integers.
Find three consecutive integers such that the sum of the first and twice the second is 17 more than twice the third.
I know that consecutive integers are x, x+1, x+2 and they are added together, but I don't know how to set up the problem.
So the first number would be x
The second number would be x+1
And the third number would be x+2
Or at least that's what I understand and have been thinking.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Solve each problem involving consecutive integers.
Find three consecutive integers such that the sum of the first and twice the second is 17 more than twice the third.
I know that consecutive integers are x, x+1, x+2 and they are added together, but I don't know how to set up the problem.
So the first number would be x
The second number would be x+1
And the third number would be x+2
:
that's right then just write an equation for the statement:
"three consecutive integers such that the sum of the first and twice the second is 17 more than twice the third."
x + 2(x+1) = 2(x+2) + 17
x + 2x + 2 = 2x + 4 + 17
3x + 2 = 2x + 21
3x - 2x = 21 - 2
You get the idea now I am sure
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