SOLUTION: how do i use the the substitution method for 9m+n=24 m-3n=12 to find the ordered pairs.

Algebra ->  Linear-equations -> SOLUTION: how do i use the the substitution method for 9m+n=24 m-3n=12 to find the ordered pairs.      Log On


   



Question 263367: how do i use the the substitution method for 9m+n=24 m-3n=12
to find the ordered pairs.

Found 2 solutions by angphy, JBarnum:
Answer by angphy(3) About Me  (Show Source):
You can put this solution on YOUR website!
9m+n=24- 1st equation
m-3n=12- 2nd equation
First, you want to get m by itself in the 2nd equation
m-3n=12 add 3n to both side of the equation to isoslate m
+3n +3n
m=3n+12. then, you can substitute in m in the 1st equation
9(3n+12)+n=24 solve to find n
27n+108+n=24
28n+108=24
-108 -108
28n=-84 divide by 28 on both side of the equation to isoslate n
n=-3
Put the value of n into the 1st equation
9m+n=24
9m+(-3)=24 add 3 to get 9m by itself
+3 +3
9m=27 Divide by 9 to isoslate m
m=3
Answer:(3,-3)


Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
fist find for one variable
9m%2Bn=24__n=24-9m
m-3n=12
pick one equation and plug it in the other
so: n=24-9m
m-3%2824-9m%29=12
m-72%2B27m=12
-72%2B28m=12
-72%2B28m%2B72=12%2B72
28m=84
m=84%2F28
m=3
_________________
m-3n=12
3-3n=12
3-3n-3=12-3
%28-3n%29%2F-3=9%2F-3
%28cross%28-3%29n%29%2Fcross%28-3%29=9%2F-3
n=-3