SOLUTION: g(x)=x^2+1 evaluate this function at g(t^2)

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Question 262379: g(x)=x^2+1

evaluate this function at g(t^2)
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
replace x with t^2 to get
g(t^2) = (t^2)^2 +1
which is
g(t^2) = t^4 + 1