SOLUTION: Write an equation in Standard form using only intergers for the line described. A line perpendicular to y=2/3x+5 (2,-3) my start: y-(-3)=-3/2(x-2) (the correct answer is 3x+

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Question 261891: Write an equation in Standard form using only intergers for the line described.
A line perpendicular to y=2/3x+5 (2,-3)
my start: y-(-3)=-3/2(x-2) (the correct answer is 3x+2y=0 but I can't get there)

Found 3 solutions by Alan3354, solver91311, Earlsdon:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
A line perpendicular to y=2/3x+5 (2,-3)
(y = (2/3)x + 5 would be better)
The slope of the given line is 2/3
Lines perpendicular to it have a slope of -3/2, the negative inverse.
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Find the equation of the line thru (2,-3) with a slope of -3/2.
Use y = mx + b and the point to find b:
-3 = (-3/2)*2 + b
b = 0
--> y = -3x/2

Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!

Sorry, not intergers, rather they are integers.

Your beginning is exactly correct.

Multiply both sides by 2:

Distribute the -3 on the right:

Add to both sides:

John

Answer by Earlsdon(6294)   (Show Source):
You can put this solution on YOUR website!
First, the slope, m, of a line that is perpendicular to the given line is the negative reciprocal of the slope of the given line.
The slope of the given line is .
The slope of the new line will be so you can start with the slope-intercept form: but substitute
Now substitute the x- and y-coordinates from the given point (2, -3) to find the value of b, the y-intercept.

Now you can finish the equation in slope-intercept form:
But you want integers only, so multiply through by 2 to get:
Finally, add 3x to both sides to get the standard form.