SOLUTION: Here are two water tanks of water. The 50 gallon is empty and is then filled at at rate of 2 gallons per minute. At the exact same time, the 140 gallon tank starts out completely f

Algebra ->  Linear-equations -> SOLUTION: Here are two water tanks of water. The 50 gallon is empty and is then filled at at rate of 2 gallons per minute. At the exact same time, the 140 gallon tank starts out completely f      Log On


   



Question 260068: Here are two water tanks of water. The 50 gallon is empty and is then filled at at rate of 2 gallons per minute. At the exact same time, the 140 gallon tank starts out completely full and is being emptied at a rate of 5 gallons per minute, when will both tanks contain the same amount of water? write an formula and graph this situation.
Found 2 solutions by richwmiller, stanbon:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
2t=140-5t
7t=140
t=20
2t*20=40
140-5*20=40
After 20 minutes they will each have 40 gallons
y=2t
y=140-5t
(20,40) is where the lines cross

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Here are two water tanks of water. The 50 gallon is empty and is then filled at at rate of 2 gallons per minute. At the exact same time, the 140 gallon tank starts out completely full and is being emptied at a rate of 5 gallons per minute, when will both tanks contain the same amount of water? write an formula and graph this situation.
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1st tank Equation:
Amount in tank = 0 + 2t gallons
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2nd tank Equation:
Amount in tank = 140 - 5t gallons
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Problem equation:
Amount in tank #1 = Amount in tank #2
0+2t = 140-5t
7t = 140
t = 20 minutes
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graph%28400%2C300%2C-10%2C30%2C-10%2C170%2C2x%2C140-5x%29
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Cheers,
Stan H.