SOLUTION: ((x^2 - x) / (x^2 + 3x + 2)) / ((x^2 + 2x)/ (x^2 -1)) or http://www.thea.nesinc.com/images/math/tasp_image335.gif

Algebra ->  Linear-equations -> SOLUTION: ((x^2 - x) / (x^2 + 3x + 2)) / ((x^2 + 2x)/ (x^2 -1)) or http://www.thea.nesinc.com/images/math/tasp_image335.gif       Log On


   

Question 255303: ((x^2 - x) / (x^2 + 3x + 2)) / ((x^2 + 2x)/ (x^2 -1))
or
http://www.thea.nesinc.com/images/math/tasp_image335.gif
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
OUr expression is:

step 1 - factor each part separately:
x^2-x = x(x-1)
x^2 + 3x + 2 = (x+2)(x+1)
x^2+ 2x = x(x+2)
x^2-1 = (x+1)(x-1)
we get
%28x%2A%28x-1%29%29%2F%28%28x%2B2%29%28x%2B1%29%29 / %28x%2A%28x%2B2%29%29%2F%28%28x%2B1%29%28x-1%29%29
step 2-Multiply the top fraction by the reciprocal of the bottom fraction to get
%28x%2A%28x-1%29%29%2F%28%28x%2B2%29%28x%2B1%29%29 * %28%28x%2B1%29%28x-1%29%29%2F%28x%2A%28x%2B2%29%29
step 3 - cancel where possible to get
%28x-1%29%5E2+%2F+%28x%2B2%29%5E2