SOLUTION: okay i need help on this problem. I've tried a lot of different strategies to get the answer but i can't seem to find the right answer. I NEED help PLEASE. Give the standard form

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Question 254981: okay i need help on this problem. I've tried a lot of different strategies to get the answer but i can't seem to find the right answer. I NEED help PLEASE.
Give the standard form of the equation of the line that is perpendicular to y=8/7x-9 and contains (8, -1).
Found 2 solutions by drk, palanisamy:
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
step 1 - solve the equation for y. We already have that as y=(8/7)x-9
step 2 - identify the slope. m = (8/7)
step 3 - we want perpendicular slope so take our slope and negative flip it to get m = (-7/8).
step 4 - put this new slope, m = -7/8 and (8, -1) into y = mx + b and solve for b. We get
y+=+mx+%2B+b
-1+=+%28-7%2F8%29%2A8+%2B+b
-6+=+b
step 5 - write the equation with your new m and b values as
y+=+%28-7%2F8%29x+-+6

Answer by palanisamy(496) About Me  (Show Source):
You can put this solution on YOUR website!
The given equation of the line is
y = (8/7)x-9
Slope of this line = 8/7
The slope of a line perpendicular to this line = -7/8
Ifthe perpendicular line passes through the point (8,-1) then its equation is
[y-(-1)] = (-7/8)(x-8)
8(y+1) = -7(x-8)
8y+8 = -7x+56
7x+8y+8-56 = 0
7x+8y-48 = 0