SOLUTION: What is the value of k if the line 2x + 3y = 3 is perpendicular to the line 2x + ky + 1 = 0?

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Question 254318: What is the value of k if the line 2x + 3y = 3 is perpendicular to the line 2x + ky + 1 = 0?
Found 3 solutions by drk, vleith, richwmiller:
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
step 1 - find the slope of
2x+%2B+3y+=+3
and solve for y to get
Y+=+%28-2%2F3%29x+%2B+1
* slope = (-2/3)
The perpendicular slope is the negative flip, or (3/2).
We solve
2x+%2B+ky+%2B+1++=++0
for y to get
y = (-2/k)x - 1/k.
The slope here is
-2/k which equals our perpendicular slope. We get
-2/k = (3/2)
k = -4/3.

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
for two lines to be perpendicular, their slopes have to have a product of -1
Find the slope of the first line
2x+%2B+3y++=++3+
3y+=+-2x+%2B+3
y+=+-%282%2F3%29x+%2B+1
So the slope is -2%2F3
Find the slope of the second line
2x+%2B+ky+%2B+1++=++0
ky+=+-2x+-+1
y+=+-%282%2Fk%29x+-1%2Fk
So the slope of the second line is -2%2Fk
Set the product of the two slopes equal to -1
%28-2%2F3%29+%2A+%28-2%2Fk%29+=+-1
4%2F3k+=+-1
k+=+-4%2F3
Plot the graphs and verify
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C+-2x%2F3+%2B1+%2C+3x%2F2+%2B+3%2F4%29

Answer by richwmiller(17219) About Me  (Show Source):