You can put this solution on YOUR website! The first thing you must understand is the numbers (or variables)in front of the ( ) are actually being multiplied to the numbers and/or variables inside the ( ). So first lets distribute the numbers that need to be multiplied throught your equation like this. your problem is stated
3(4z-1)-2(2+2)=2(z+1) first I will take the 3 and mult. into the ( ).
12z-3-2(2+2)=2(z+1) I do the rest the same way.
12z-3-4+4=2z+2 do you see how I multiplied the numbers outside () to inside?
then you move your numbers and variables to opposite sides of the = signs, remember to change your +/- signs when you cross the = sign. so you will have
12z-2z=3+4-4+2
10z=5 you still have a 10 in front, so you must divide each side by 10
10z/10=5/10
z=5/10
z=1/2
does this help?
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